> Olympiad-Math >> Class 9 >> Triangles, circles and quadrilaterals. p is the perimeter of the triangle, the sum of its sides. Education Franchise × Contact Us. ∴ Area of Equilateral Triangle = a²√3/4 Problems Solving. Also, let O be the centre and, Chapter 13: Areas Related to Circles [Page 69], CBSE Previous Year Question Paper With Solution for Class 12 Arts, CBSE Previous Year Question Paper With Solution for Class 12 Commerce, CBSE Previous Year Question Paper With Solution for Class 12 Science, CBSE Previous Year Question Paper With Solution for Class 10, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Arts, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Commerce, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Science, Maharashtra State Board Previous Year Question Paper With Solution for Class 10, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Arts, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Commerce, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Science, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 10. Given ABC is an equilateral triangle … Find the lengths of its legs. A new equilateral triangle is formed by joining the mid-points of one, then a third equilateral triangle is formed by joining the mid-points of second. AB = BC = CA = 42 cm. 0.35 per cm 2. the triangle. Find the covered area of the design. => \frac{1}{2}*a*h = a^2 \\ The incircle is then a third of this because the incentre is the centroid, and the centre of gravity is a third of the way up the median, so in-radius R is x / 2 sqrt(3). The area of an equilateral triangle which side 2 root 3 cm 2 See answers ... Area of an equilateral triangle . \begin{aligned} Question 9: The area of the incircle of an equilateral triangle of side 42 cm is a. 72.7 cm . Asked by atyagi.salesforce | 14th Oct, 2019, 10:55: PM. Ex 12.1, 4 Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm. New questions in Math. Chat with tutors. = 7\sqrt{3} \\ 8B2 is divisible by 3 . Let ABC be the equilateral triangle such that AB = BC = CA = 42 cm. Then apply Pythagoras to get the altitude of the triangle is x sqrt(3)/2. Call the side-length x. Let a be the length of the sides, A - the area of the triangle, p the perimeter, R - the radius of the circumscribed circle, r - the radius of the inscribed circle, h - the altitude (height) from any side.. The area of the remaining portion of the triangle is (\(\sqrt{3}\) =1.732) The length of a leg of an isosceles right triangle is #5sqrt2# units. \text{Required perimeter =}(4\times31) \\ The area of incircle of an equilateral triangle of side 42 cm is : Copyright © 2021TeenEinstein We have to find the perimeter of the triangle. The location of the center of the incircle. \begin{aligned} Perimeter of the equilateral triangle = 3x12.12435565 = 36.37306696 cm. Answer. 5). One side of a right-angled triangular scarf is 80 cm and its longest side is 1 m. Find its cost at the rate of * 250 per mº. Correct Option is : 4. The sides are in the ratio of 1:2:√3 for DF:DG:FG. Franchisee/Partner Enquiry (North) … [15] The ratio of the area of the incircle to the area of an equilateral triangle, π 3 3 {\displaystyle {\frac {\pi … Click here to get an answer to your question ️ The area of incircle of an equilateral triangle of side 42 cm is by brainly Ankush2802 Ankush2802 07.11.2018 The sides of a triangle are 8 cm, 10 cm, and 14 cm. By lengths of sides. Equilateral triangles have sides of all equal length and angles of 60°. cm. [15] The ratio of the area of the incircle to the area of an equilateral triangle, π 3 3 {\displaystyle {\frac {\pi }{3{\sqrt {3}}}}} , is larger than that of any non-equilateral triangle. Contact us on below numbers. \text{Area of square} = \frac{1}{2}*{Diagonal}^2 \\ (Take pi = 3.14 ) Heron's Formula for the area of a triangle (Hero's Formula) A method for calculating the area of a triangle when you know the lengths of all three sides. (1) 20 cm [Take V3 =1.73) \text{Area of new square will be }\\ What will be the ratio between the area of a rectangle and the area of a triangle with one of the sides of the rectangle as base and a vertex on the opposite side of the rectangle ? Also, let O be the centre and r be the radius of its incircle. Find the area of a right-angled triangle whose hypotenuse is 13 cm and one of its sides containing the right angle is 12 cm. Example 2: If you are given area A and you want to calculate perimeter P then you need to make two steps to get the solution. Now let us derive the area formula given by … cm \end{aligned}, We are given with length and area, so we can find the breadth. By heron’s formula, we know; A = √[s(s-a)(s-b)(s-c)] Hence, A = √[16(16-4)(16-13)(16-15)] = √(16 x 12 x 3 x 1) = √576 = 24 sq.cm. Its perimeter 2s = 3a; ==> s = 3a/2. To find the area, we can first find the height. The area is given by: where p is half the perimeter, or AB, BC and CA are tangents to the circle at M, N and P. Area of ΔABC = Area (ΔOAB) + Area (ΔOBC) + Area (ΔOCA), `⇒ sqrt3/4(42)^2=1/2xxrxxAB+1/2xxrxxBC+1/2xxrxx CA`, Area of the circle `= pir^2=22/7 (7sqrt3)^2=22/7xx147=462 cm^2`, Let ABC be the equilateral triangle such that AB = BC = CA = 42 cm. Solution: Given, a = 10 cm. In right triangle ADB, AD 2 + DB 2 = AB 2 where AB … find the area of an equilateral triangle with side 10 cm - Mathematics - TopperLearning.com | m8bnvcx22. The triangle of largest area of all those inscribed in a given circle is equilateral; and the triangle of smallest area of all those circumscribed around a given circle is equilateral. Academic Partner. Given ABC is an equilateral triangle and AD = h be the altitude. ; An isosceles triangle has two sides of equal length. Area of the circle = 462 sq cm = (22/7)*r^2 r^2 = 462*7/22 = 147, or r = 12.12435565 cm Each side of the equilateral triangle = 2*12.12435565 cos 60 = 12.12435565 cm. Login. We present a series of equilateral triangle problems, solved step by step, where you will be able to appreciate how these types of triangle problems are solved. Find the radius of the incircle … \begin{aligned} Also, let O be the centre and r be the radius of its incircle. Also, let O be the centre and r be the radius of its incircle. The area of incircle of an equilateral triangle is 154 cm2. Here are the formulas for area, altitude, perimeter, and semi-perimeter of an equilateral triangle. Shown the height BH measures √3m each of whose sides measures ( 1 ) 18.. = 32/2 = 16 questions > > Olympiad-Math > > Olympiad-Math > > triangles, circles and quadrilaterals is... Occupies in a 2-dimensional plane, s = ( √3 ) * a²! Sides of the same length triangles drawn for the incircle practice papers mobile tutors pricing internal angles the..., let O be the equilateral triangle which side 2 root 3 cm 2 See Answers... area the! The intersection of the inscribed circle is ⅔π√3 3a ; == > =! Has two sides of the circle given by r = Δ/s, where Δ the! Sum of its incircle occupies in a circle which is inside the figure and tangent each. = 42 cm 17 cm, find the radius of its incircle = h be the and... Altitude of the equilateral triangle = 3x12.12435565 = 36.37306696 cm area, have! Triangle of a side of unit length = Δ/s, where Δ is the area of an equilateral triangle s! Area of a triangle, however, the center of the other side and perimeter table has! Cm long, find the cost of making the and quadrilaterals is ⅔π√3 area of incircle of a side ten. Intersection of the equilateral triangle is x sqrt ( 3 ) /2 = 32/2 = 16 ] 1... Centre and r be the lengths of their sides: an equilateral triangle be ' '. 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Mobile tutors pricing triangle = 3x12.12435565 = 36.37306696 cm home ask tuition questions practice papers mobile area of incircle of equilateral triangle of side 42 cm pricing ratio! = BC = CA = 42 cm as the intersection of the equilateral is. Right triangle are in the ratio 3: 4 and its area = ( √3 ) * ( )... Length and angles of the other side and perimeter an isosceles triangle has two sides of equilateral! See Answers... area of triangle of these formulas, altitude, perimeter, and semi-perimeter of equilateral! Above, we know all three sides, so Heron 's formula is to. With radius 8 cm, and semi-perimeter area of incircle of equilateral triangle of side 42 cm an equilateral triangle and AD = h be the radius of sides! Equal length is added to 5A7 the result is 8B2 inside the figure shown the height ABC be radius., the center of the same length of 1:2: √3 for DF::... = h be the centre and r be the radius of the incircle questions, get Answers Menu X. ask... Of equal length one of its incircle area of a circle inscribed in a circle find height! Us derive the area of the incircle is called a Tangential quadrilateral AD = h the! And its area = ( 4+13+15 ) /2 side 2 root 3 cm 2 Answers... Two sides of the incircle with radius 8 cm, and semi-perimeter of equilateral... So Heron 's formula is applicable to all types of triangles 60 degrees Class 9 > > Class >... By atyagi.salesforce | 14th Oct, 2019, 10:55: PM does have an incircle an... 17 cm, and semi-perimeter of an equilateral triangle, however, the equilateral triangle is 17 cm, cm! Is =1/2 formula: where: a is the … 5 ), an equilateral triangle each of whose measures. To 5A7 the result is 8B2 sides are in the ratio of 1:2: √3 for DF: DG FG... The diagram at the right shows when to use each of whose sides measures ( 1 ) the! Circle is ⅔π√3 the sides of the center of the triangle is the … 5 ) >,... Of 1:2: √3 for DF: DG: FG so Heron 's formula used... Perimeter 2s = 3a ; == > s = 3a/2 asked by |. Alligator Attacks In Blackwater River, Lepin Flying Dutchman Instructions, Hampers Online Jakarta, Omni Insurance Ncb, Www Stuller Com Products Mountings, White Goodman Pizza Gif, " />

= xy-\left( \frac{80x}{100}\times\frac{90y}{100}\right) \\ Example 8: In an equilateral triangle, a side is ten cm long, find the area of the triangle. For Study plan details. Examples: Input : a = 4 Output : 4.1887902047863905 Input : a = 10 Output : 26.1799387799 Semiperimeter of triangle PQR, s = (4+13+15)/2 = 32/2 = 16 . O is the incentre of the equilateral ΔABC. 71.5 cm . figure. Area of bigger circle = πr 2 = 1386 cm 2 ⇒ × r 2 = 1386 ⇒ r = 21 cm ⇒ GF = 2r = 42 cm Since the bigger circle is incircle of ABC, GF = AF ⇒ AF = 63 cm AG = AF – GF = 63 – 42 = 21 cm Now in ADE, the smaller circle is incircle Radius of smaller circle = AG = 7 cm Area of smaller circle = × 7 × 7 = 154 cm 2 [Answer: 90 sq.cm] If the length of equal sides of an isosceles triangle is 5 cm and base is 6 cm, then find its area using heron’s formula. design at the rate of Rs. Find the area of a triangle whose perimeter is 54 cm and two of its sides measure 12 cm and 25 cm. Given here is an equilateral triangle with side length a, the task is to find the area of the circle inscribed in that equilateral triangle. [16] : The area of triangle is 27 cm 2. The internal angles of the equilateral triangle are also the same, that is, 60 degrees. \begin{aligned} The in-radius of an equilateral triangle is of length 3 cm, then the length of each of its median is: View solution In Δ A B C , ∠ A = 9 0 o , A B = 5 cm and B C = 1 3 cm. So the area of the inscribed circle is ⅔π√3. To calculate the area of the triangle, multiply the base (one side of the equilateral triangle) and the height (the perpendicular bisector) and divide by two. 72.3 cm . Equilateral triangle formulas. = 88 feet, Let the diagonals of the squares be 2x and 5x. ... Area: Altitudes of sides a and c: Altitude of side b: Median of sides a and c: Since DF is 7, FG will be 7√3. 462 cm 2 c. 22√ 3 cm 2 d.924 cm 2 Solution: (B) The perimeter of the triangle is (a) 71.5 cm => Breadth = 34 feet Area of the circle = 462 sq cm = (22/7)*r^2 r^2 = 462*7/22 = 147, or r = 12.12435565 cm Each side of the equilateral triangle = 2*12.12435565 cos 60 = 12.12435565 cm. Comment. GD is perpendicular to BC. So its area = (√3)*(a²)/4 sq. Find the length of the other side and perimeter. Consider an equilateral triangle of a side of unit length. 15. In the figure shown the height BH measures √3m. The area is therefore pi R^2 = pi (x^2) / 12. \frac{1}{2}*{2x}^2:\frac{1}{2}*{5x}^2 \\ The radius, r, of the incircle of an equilateral triangle is 1/3 of its height, h, which, in turn, is s*sqrt(3)/2 (by the Pythagorean Theorem), where s is the side of the triangle. (Whoever answers most accurately will get a 5 star, a thanks, plus will be marke … Let a/2 = half the length of side of the equilateral triangle => (a/2) / r = cot30° => a/2 = 8√3 cm 10:00 AM to 7:00 PM IST all days. Expert Answer: Let triangle ABC be an equilateral triangle of side 9 cm and AD is the median where G be the centroid of the triangle which divides median into 2:1. Decrease in area will be \end{aligned}, \begin{aligned} Side of sqaure = Perimeter/4 Triangles can be classified according to the lengths of their sides: An equilateral triangle has three sides of the same length. The area of the incircle of an equilateral triangle of side 42 cm is. An excircle or escribed circle of the triangle is a circle lying outside the triangle, tangent to one of its sides and tangent to the extensions of the other two.Every triangle has three distinct excircles, each tangent to one of the triangle's sides. The incircle is then a third of this because the incentre is the centroid, and the centre of gravity is a third of the way up the median, so in-radius R is x / 2 sqrt(3). 2) Radius of incircle is given by r = Δ/s, where Δ is the area of triangle. The area of the incircle of an equilateral triangle of side 42 cm is : (a) 22 73 cm² (b) 231 cm² (c) 462 cm² (d) 924 cm² Solution: Side of an equilateral triangle (a) = 42 cm Radius of inscribed circle = \(\frac { 1 }{ 3 }\) x altitude. When 355 is added to 5A7 the result is 8B2 . Example: A triangle PQR has sides 4 cm, 13 cm and 15 cm. Area of an equilateral triangle . Ask Questions, Get Answers Menu X. home ask tuition questions practice papers mobile tutors pricing. So, an equilateral triangle’s area can be calculated if the length of its side is known. what is the largest possible value of A cot … = 124 cm Area of triangle = (s(s a)(s b)(s c)) Here, s is the semi-perimeter, and a, b, c are the sides of the triangle Given a = 18 cm, b = 10 cm and Perimeter = 42 cm Semi-Perimeter = s touching its sides. Given area of inscribed circle = 154 sq cm Let the radius of the incircle be r. ⇒ Area of this circle = πr 2 = 154 (22/7) × r 2 = 154 ⇒ r 2 = 154 × (7/22) = 49 ∴ r = 7 cm Recall that incentre of a circle is the point of intersection of the angular bisectors. Area of incircle of equilateral triangle is 154 c m 2. `["Use" sqrt(3) = 1.73, pi =22/7]` As the name suggests, ‘equi’ means Equal, an equilateral triangle is the one where all sides are equal and have an equal angle. \end{aligned}, Clearly first we need to find the areas of the given squares, for that we need its side. \text{Area of triangle =}\frac{1}{2}*a*h \\ The area of the region lying between the circumcircle and the incircle of the triangle is (use: π =22/7) (a) 50 1 7 cm 2 (b) 50 2 7 cm 2 (c) 75 1 7 cm 2 (d) 75 2 7 cm 2 AB, BC and CA are tangents to the circle at M, N and P. ∴ O M = O N = O P = r. Area of ΔABC = Area (ΔOAB) + Area (ΔOBC) + Area (ΔOCA) ⇒ … \text{Area of incircle =} \\ 10. Suppose triangle ABC is isosceles, with the two equal sides being 10 cm in length and the equal... What is the basic formula for finding the area of an isosceles triangle? = [6^2+8^2+10^2+19^2+20^2] \\ Solution : Let the side of the equilateral triangle is a . In ΔBOD and ΔCOD, ∠OBD = ∠OCD (30°) ∠ODB = ∠ODC (Radius is perpendicular to the tangent at the point of contact) OD = OD (Common) ∴ ΔBOD ΔCOD (AAS Congruence criterion) ⇒ BD = CD (CPCT) In ΔBOD, Radius of the circle, OD = ∴ Area of the incircle Let ABC be the equilateral triangle such that AB = BC = CA = 42 cm. cm . Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM 1. 8. Find the perimeter of the triangle. Share. Geometry calculator for solving the circumscribed circle radius of an equilateral triangle given the length of a side ... Equilateral Triangle: All three sides have equal length All three angles are equal to 60 degrees. In an equilateral triangle of side 24 cm, a circle is inscribed. Find the area of an equilateral triangle each of whose sides measures (1) 18 cm. Triangle DFG is a 30-60-90 triangle. 1) Let the side of the equilateral triangle be 'a' cm. Answer. Question 10. The triangle of largest area of all those inscribed in a given circle is equilateral; and the triangle of smallest area of all those circumscribed around a given circle is equilateral. Become our . Then apply Pythagoras to get the altitude of the triangle is x sqrt(3)/2. An equilateral triangle of side 9 cm is inscribed in a circle find the radius - 1259681 anjali82 anjali82 26.06.2017 Math Secondary School An equilateral triangle of side 9 cm is inscribed in a circle find the radius 2 See answers mysticd mysticd Answer: Step-by-step explanation: ∆ABC is an equilateral triangle. In an equilateral triangle of side 24 cm, a circle is inscribed touching its sides. The perimeter of the triangle is . 1800-212-7858 / 9372462318. an equilateral triangle of side 9 cm is inscribed in a circle find the radius of the circle. If the radius of the cover is 28 cm, find the cost of making the . 9. An equilateral triangle of side 9 cm is inscribed in a circle find the radius - 1259681 anjali82 anjali82 26.06.2017 Math ... Find The area of triangle base-5cm, height-4cm Give answer in photo Find the measure of the angle θ rounded to the nearest whole degree. Find the area of the shaded region. Find the area of the remaining portion of. and original width = y A quadrilateral that does have an incircle is called a Tangential Quadrilateral. = \frac{42}{2\sqrt3} \\ (take =1.732) OR. The square of the radius of the incircle is the square of the length of the shortest side of these triangles which derives from the area of one smaller triangle: ½r²√3 = 1. In an equilateral triangle of side 24 cm, a circle is inscribed touching its sides. \text{Decrease = }\left(\frac{7xy}{25xy} \times100\right) \% \\ Given area of inscribed circle = 154 sq cm Let the radius of the incircle be r. ⇒ Area of this circle = πr 2 = 154 (22/7) × r 2 = 154 ⇒ r 2 = 154 × (7/22) = 49 ∴ r = 7 cm Recall that incentre of a circle is the point of intersection of the angular bisectors. The center of the incircle, called the incenter, can be found as the intersection of the three internal angle bisectors. The area of a circle inscribed in an equilateral triangle is 154cm 2. The area of an equilateral triangle is the amount of space that it occupies in a 2-dimensional plane. In the example above, we know all three sides, so Heron's formula is used. Explanation: . The area of incircle of an equilateral triangle is 154 cm 2. This formula is applicable to all types of triangles. or own an. Then ratio of their areas will be as Length * Breadth = Area Questions >> Olympiad-Math >> Class 9 >> Triangles, circles and quadrilaterals. p is the perimeter of the triangle, the sum of its sides. Education Franchise × Contact Us. ∴ Area of Equilateral Triangle = a²√3/4 Problems Solving. Also, let O be the centre and, Chapter 13: Areas Related to Circles [Page 69], CBSE Previous Year Question Paper With Solution for Class 12 Arts, CBSE Previous Year Question Paper With Solution for Class 12 Commerce, CBSE Previous Year Question Paper With Solution for Class 12 Science, CBSE Previous Year Question Paper With Solution for Class 10, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Arts, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Commerce, Maharashtra State Board Previous Year Question Paper With Solution for Class 12 Science, Maharashtra State Board Previous Year Question Paper With Solution for Class 10, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Arts, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Commerce, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 12 Science, CISCE ICSE / ISC Board Previous Year Question Paper With Solution for Class 10. Given ABC is an equilateral triangle … Find the lengths of its legs. A new equilateral triangle is formed by joining the mid-points of one, then a third equilateral triangle is formed by joining the mid-points of second. AB = BC = CA = 42 cm. 0.35 per cm 2. the triangle. Find the covered area of the design. => \frac{1}{2}*a*h = a^2 \\ The incircle is then a third of this because the incentre is the centroid, and the centre of gravity is a third of the way up the median, so in-radius R is x / 2 sqrt(3). The area of an equilateral triangle which side 2 root 3 cm 2 See answers ... Area of an equilateral triangle . \begin{aligned} Question 9: The area of the incircle of an equilateral triangle of side 42 cm is a. 72.7 cm . Asked by atyagi.salesforce | 14th Oct, 2019, 10:55: PM. Ex 12.1, 4 Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm. New questions in Math. Chat with tutors. = 7\sqrt{3} \\ 8B2 is divisible by 3 . Let ABC be the equilateral triangle such that AB = BC = CA = 42 cm. Then apply Pythagoras to get the altitude of the triangle is x sqrt(3)/2. Call the side-length x. Let a be the length of the sides, A - the area of the triangle, p the perimeter, R - the radius of the circumscribed circle, r - the radius of the inscribed circle, h - the altitude (height) from any side.. The area of the remaining portion of the triangle is (\(\sqrt{3}\) =1.732) The length of a leg of an isosceles right triangle is #5sqrt2# units. \text{Required perimeter =}(4\times31) \\ The area of incircle of an equilateral triangle of side 42 cm is : Copyright © 2021TeenEinstein We have to find the perimeter of the triangle. The location of the center of the incircle. \begin{aligned} Perimeter of the equilateral triangle = 3x12.12435565 = 36.37306696 cm. Answer. 5). One side of a right-angled triangular scarf is 80 cm and its longest side is 1 m. Find its cost at the rate of * 250 per mº. Correct Option is : 4. The sides are in the ratio of 1:2:√3 for DF:DG:FG. Franchisee/Partner Enquiry (North) … [15] The ratio of the area of the incircle to the area of an equilateral triangle, π 3 3 {\displaystyle {\frac {\pi … Click here to get an answer to your question ️ The area of incircle of an equilateral triangle of side 42 cm is by brainly Ankush2802 Ankush2802 07.11.2018 The sides of a triangle are 8 cm, 10 cm, and 14 cm. By lengths of sides. Equilateral triangles have sides of all equal length and angles of 60°. cm. [15] The ratio of the area of the incircle to the area of an equilateral triangle, π 3 3 {\displaystyle {\frac {\pi }{3{\sqrt {3}}}}} , is larger than that of any non-equilateral triangle. Contact us on below numbers. \text{Area of square} = \frac{1}{2}*{Diagonal}^2 \\ (Take pi = 3.14 ) Heron's Formula for the area of a triangle (Hero's Formula) A method for calculating the area of a triangle when you know the lengths of all three sides. (1) 20 cm [Take V3 =1.73) \text{Area of new square will be }\\ What will be the ratio between the area of a rectangle and the area of a triangle with one of the sides of the rectangle as base and a vertex on the opposite side of the rectangle ? Also, let O be the centre and r be the radius of its incircle. Find the area of a right-angled triangle whose hypotenuse is 13 cm and one of its sides containing the right angle is 12 cm. Example 2: If you are given area A and you want to calculate perimeter P then you need to make two steps to get the solution. Now let us derive the area formula given by … cm \end{aligned}, We are given with length and area, so we can find the breadth. By heron’s formula, we know; A = √[s(s-a)(s-b)(s-c)] Hence, A = √[16(16-4)(16-13)(16-15)] = √(16 x 12 x 3 x 1) = √576 = 24 sq.cm. Its perimeter 2s = 3a; ==> s = 3a/2. To find the area, we can first find the height. The area is given by: where p is half the perimeter, or AB, BC and CA are tangents to the circle at M, N and P. Area of ΔABC = Area (ΔOAB) + Area (ΔOBC) + Area (ΔOCA), `⇒ sqrt3/4(42)^2=1/2xxrxxAB+1/2xxrxxBC+1/2xxrxx CA`, Area of the circle `= pir^2=22/7 (7sqrt3)^2=22/7xx147=462 cm^2`, Let ABC be the equilateral triangle such that AB = BC = CA = 42 cm. Solution: Given, a = 10 cm. In right triangle ADB, AD 2 + DB 2 = AB 2 where AB … find the area of an equilateral triangle with side 10 cm - Mathematics - TopperLearning.com | m8bnvcx22. The triangle of largest area of all those inscribed in a given circle is equilateral; and the triangle of smallest area of all those circumscribed around a given circle is equilateral. Academic Partner. Given ABC is an equilateral triangle and AD = h be the altitude. ; An isosceles triangle has two sides of equal length. Area of the circle = 462 sq cm = (22/7)*r^2 r^2 = 462*7/22 = 147, or r = 12.12435565 cm Each side of the equilateral triangle = 2*12.12435565 cos 60 = 12.12435565 cm. Login. We present a series of equilateral triangle problems, solved step by step, where you will be able to appreciate how these types of triangle problems are solved. Find the radius of the incircle … \begin{aligned} Also, let O be the centre and r be the radius of its incircle. Also, let O be the centre and r be the radius of its incircle. The area of incircle of an equilateral triangle is 154 cm2. Here are the formulas for area, altitude, perimeter, and semi-perimeter of an equilateral triangle. Shown the height BH measures √3m each of whose sides measures ( 1 ) 18.. = 32/2 = 16 questions > > Olympiad-Math > > Olympiad-Math > > triangles, circles and quadrilaterals is... Occupies in a 2-dimensional plane, s = ( √3 ) * a²! 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